Question

$\huge\mathcal{\fcolorbox{lime}{black}{\orange{•Question:-}}}$


Find the perimeter of an isosceles triangle whose one side is 10 cm greater than each of its equal sides and perimeter is 100 cm.​

Answer 1

I hope it helps you thank you

Answer 2

Step-by-step explanation:

➨ Given :

• Find the perimeter of an isosceles triangle whose one side is 10 cm greater than each of its equal sides and perimeter is 100 cm.

➨ To Find :

• The perimeter of an isosceles triangle.

➨ Solution :

Let the length of each of the equal sides be x cm.

Then, length of the unequal side will be (x+10) cm.

‏‏‎ ‎

‏‏‎ ‎

➨ $\bf\green{According \: to \: the \: question,}$

Perimeter = 3x + 10 = 100

$\implies$3x + 10 = 100

$\implies$ 3x = 90

$\implies$ x = 30

∴ The sides are 30 cm, 30 cm & 40 cm.

➨ As we know,

$\bf\red{\fbox{Perimeter \: of \: a \: triangle = a + b + c}}$

∴ Perimeter = 30 + 30 + 40 = 100 cm.