Question

$\huge \mathcal \pink{Q} \red{ue } \purple{s} \blue{t} \red{i} \pink{o} \green{n}$

Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of reservoir is 108m³. Find the number of hours it will take to fill the reservoir.
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Answer 1

$\large\bf{\underline\orange{Answer \:↝}}$

Question :-

Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of reservoir is 108m³. Find the number of hours it will take to fill the reservoir.

Answer :-

Volume of cuboidal tank, V = 108 m³

1 m³ = 1000litres

Hence,

V = 108×1000

= 108000 litres

Rate of water flow , Q = 60 litres/minutes

Hence,

Time taken to fill the tank = V/Q

= 108000/60

= 1800 minutes

= 30 hours

In 30 hours it will take to fill the reservoir.

Answer 2

$\huge \tt \pink{Q} \red{ue} \pink{s} \red{t} \pink{i} \red{o} \pink{n}$

Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of reservoir is 108m³. Find the number of hours it will take to fill the reservoir.

$\huge \colorbox{plum}{Solution}$

Volume of reservoir =108 m³

Rate of pouring water in it = 60L/m

$\frac{60}{1000} m3/hour$

$\frac{60 \times 60}{1000} water \: filled \: in \: reservoir \\ will \: take = 1hour \\ {1m}^{3} water \: filled \: in \: reservoir \: will \\ take = \frac{1000}{60 \times 60}$

${108m}^{3} \: water \: filled \: in \: reservoir \\ will \: take = \frac{108 \times 1000}{60 \times 60} hours \\ = \pink3 \pink0 \: {\pink{hours}}$