Question

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A man Sold two cycles at Rs. 960 each. On one, he gained 20% and on the other , he lost 20%. Find his net gain % or loss % in the whole transaction.​

Answer 1

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4% loss

Step-by-step explanation:

Cycle 1

SP = 960 rupees

profit = 20%

SP = CP + Profit

SP = CP + 20% of CP

SP = 1.2 CP

CP = SP/1.2 = 960/1.2 = 800 RUPEES

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Cycle 2

SP = 960 rupees

LOSS = 20%

SP = CP - loss

SP = CP  - 20% of CP

SP = 0.8 CP

CP = SP/0.8 = 960/0.8 = 1200 RUPEES

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CP of both cycle = 800 + 1200 = 2000 rupees

SP of both cycle = 960 + 960 = 1920 rupees

loss = 2000 - 1920 = 80 rupees

% loss = (loss / CP) * 100 = 80/2000 * 100 = 4%

Answer 2

Step-by-step explanation:

Given that:-

A man sold two bicycles for Rs. 960 each.On one he gained 20% and on other he lost 20% .

To find:- his net gain or loss

Solution:-

S.P of each bicycle=960

C.P of first cycle on that he gained

S.P=C.P+Profit

=>x+20x/100

=>x+x/5

=>6x/5

=>x=960×5/6

=>x=800

C.P of profit making bicycle=>Rs 800

Now,C.P of loss making bicycle:-

S.P=C.P-Loss

=>x-20x/100

=>80x/100

=>4x/5

=>960=4x/5

=>x=960×5/4

x=Rs.1200

So,C.P of loss making bicycle =Rs.1200

Net S.P=960+960=1920

Net C.P 1200+800=2000

=>Net loss=2000-1920

=Rs.80

Net loss %=Net loss C.P×100

=>(80/2000)×100

=>4%

Hence he has net loss%=4%