Math, asked by alizayhassan022, 11 months ago

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If the sum of two numbers is 7 and the sum of their cubes is 133, find the sum of their squares.

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Answers

Answered by Battleangel
2

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let one of the number be X

and second be y

x + y = 7

 {x}^{3}  +  {y}^{3}  = 133

 {(x + y)}^{3}  =  {x}^{3}  +  {y}^{3}  + 3xy + (x + y)

 {7}^{3}  = 133 + 3xy(7)

343 = 133 + 21xy \\ hence \: xy \:  = 10

 {(x + y)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy

 {7}^{2}  =  {x}^{2}  +  {y}^{2}  + 20

49 - 20 =  {x}^{2}  +  {y}^{2}

hence the sum of their square =29

Answered by beckyrenju
0

Step-by-step explanation:

Hi Alizzay here is your answer

Given,

Sum of Two numbers = 7

Sum of two cube numbers = 133

To find

SUM OF THEIR SQUARES

PROOF :-

numbers whose sum is 7

  1. 2+5
  2. 3+4

3. 1+6

1. 2 cube = 8

5 cube = 125

2. 3 cube = 27

4 cube = 64

3. 1 cube = 1

6 cube = 216

1. is the answer since

2 cube + 5 cube

8 + 125

133

Sum of their square

2 square + 5 square

4 + 25

29

I HAVE NOT SOLVED IN A COMPLEXED MANNER, BUT IN AN EASY WAY

HOPE THIS HELPS YOU SISTER

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