Question

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An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level , how long will it take to reach - 350m

Answer 1

Answer:

60 minutes or 1 hour.

Step-by-step explanation:

Given, descending speed of elevator = 6m/min

Descends starts from 10 m above the ground level.

To find the time required to reach 350 m below ground level.

Here, since  the descend starts from 10 m above ground level, the elevator will have to cover an extra distance of 10m. So, total distance = 350 + 10 = 360 m.

Speed = 6m/min

Total distance = 360 m

So, total time taken = total distance/speed

⇒ time = 360/6

⇒ time = 60 minutes

Hence, time required to go 350 m below ground level when the elevator starts from 10 m above, is 60 minutes or 1 hour.

Answer 2

Answer:

The rate of 6m/min means that, in every minute, it goes down by 6m

We have 10 above the ground and 350 m below the ground

Note:

-350 m, means it is 350 m below the ground

Total distance = 10 + 350

                      = 360 m

Time taken = 360/6

                 = 60 minutes

OR

1 hour