Physics, asked by Anonymous, 4 months ago

tex]\huge\mathcal{Question}[/tex]

{⟹}The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time period of the vibration?

{⟹}A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.​

Answers

Answered by cuteeeepresent
5

Answer:

Frequency = 500 vibrations/second. = (1/500) = 0.002 sec...

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Answered by Anonymous
19

\huge\red{\underline{{\bf Answer\:1 :-}}}

{:⟹} Frequently = 500 Hz

{:⟹} Time period = 1/Frequency

{:⟹} 1/500

{:⟹} 0.002 seconds

\huge\red{\underline{{\bf Answer\:2 :-}}}

{:⟹} No.of oscillations in 4 seconds = 40

{:⟹} No.of oscillations in 1 second (frequency) = 4/40

{:⟹} 10 Hz

{:⟹} Time period = 1/Frequency

{:⟹} 1/10

{:⟹} 0.1 second

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