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The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time period of the vibration?
A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.
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Answered by
5
Answer:
Frequency = 500 vibrations/second. = (1/500) = 0.002 sec...
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Answered by
19
Frequently = 500 Hz
Time period = 1/Frequency
1/500
0.002 seconds
No.of oscillations in 4 seconds = 40
No.of oscillations in 1 second (frequency) = 4/40
10 Hz
Time period = 1/Frequency
1/10
0.1 second
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