Question

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Solve this questions correctly.


1. Find the angle which is five times its complement.

2. Find the angle which is four times its supplement.

3. Find the measure of an angle which is 25 more than its complement.

4. Find the measure of an angle which is 32° less than its supplement.

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Answer 1

Answer:

1> Let the smaller angle be x. Then the larger angle = 5x.

=> x + 5x = 90

=> 6x = 90

=> x = 15 degrees

Larger angle = 5(15) = 75 degrees

So, the smaller angle is 15 degrees and the larger angle is 75 degrees.

2> Let the angle be x

Then its supplement = 4x

x+4x = 180

5x = 180

x = 180/5

x = 36

So , the reqiured number is 4x = 36(4)

= 144°

3> If the sum of measure of two angles is 90 degree, they are said to be complementary angles.

Therefore the given angles are X and X+25

X+X+25=90

2x+25=90

2x=90-25

2x=65

X=65/2

X=32 1/2

4> let the angle be x

and other side be x-32

then

A/Q

x+x+32=180(supplement)

2x+32=180

2x=180-32

x=148/2

x=74

then,

x+32=74+32=106

Hope it helps you... Also, pls mark it as brainliest!!

Answer 2

Answer:

1.Let the angle be x.

Its complementary angle = 90 - x

According to the given condition, we hav:

x = 5(90 - x)

x + 5x = 450

6x = 450

x = 75

Thus, the measure of the angle is 75 degrees.

2.Here's what we know:

180 - x = 4(90-x) (supplementary angles add together to make 180 degrees. Complementary create 90 degrees. This particular angle's supplementary's partner is 4 times as large as its complementary's partner)

180 - x = 360 - 4x

180 + 3x = 360

3x = 180

x = 60.