Question

$\huge \mathcal \red{Question}$
How much water should be mixed with 12 mL of alcohol so as to obtain 12% alcohol solution?

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Answer 1

Answer: 88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.12

Answer 2

88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.

Explanation:

Let the volume of the water be x

Volume of alcohol =12 mL

Volume of the solution = x+12

Percentage of solution = 12% by volume

v/v\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100v/v%=

Mass of solution

Mass of solute

×100

12\%=\frac{12 mL}{x+12mL}\times 10012%=

x+12mL

12mL

×100

x = 88 mL

88 milliliter water should mix in 12 ml of alcohol so as to obtain 12% of alcohol solution.