Question

$\huge{\mathcal{\underline{\green{QuEsTiOn}}}}$

➪➪Prove ✍︎

$\frac{tan( \alpha )}{1 -cot( \alpha ) } + \frac{cot( \alpha )}{1 - \tan( \alpha ) } = 1 + tan( \alpha ) + \cot( \alpha )$
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Answer 1

Answer:

$\huge{\mathcal{\underline{\green{QuEsTiOn}}}}$

$\frac{tan( \alpha )}{1 - cot( \alpha )} + \frac{cot( \alpha )}{1 - tan( \alpha )} = 1 + tan( \alpha ) +cot( \alpha )$

$\huge{\mathcal{\underline{\green{AnSwER}}}}$

L.H.S = $\frac{tan}{1 - cot} + \frac{cot}{1 - \: tan}$

Answer 2

$\huge\underline\mathfrak{\red{✨ANSWER✨}}$