Physics, asked by MysteriousAryan, 2 days ago

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A 1 kg block situated on a rough incline is connected to a spring of spring constant 10N/m as shown in the attached figure .The block is released from rest with the spring in the unstretched position. The block moves 10cm down the incline before coming to rest. Find the coefficient of friction between the block and the incline. Assume that the spring has a negligible mass and the pulley is frictionless.​

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Answered by TamilQueen001
1

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Answered by OoAryanKingoO78
55

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A 1 kg block situated on a rough incline is connected to a spring of spring constant 10N/m as shown in the attached figure .The block is released from rest with the spring in the unstretched position. The block moves 10cm down the incline before coming to rest. Find the coefficient of friction between the block and the incline. Assume that the spring has a negligible mass and the pulley is frictionless

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Given :-

Word problems

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━☞To find :-

the number

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At the equilibrium the normal reaction is given as,

N=mgcos37 ∘

The frictional force is given as,

f=μN

=μmgcos37 ∘

The net force acting on the block is given as,

F=mgsin37 ∘ −μmgcos37 ∘

Since, the work done by the block will be equal to the potential energy of the spring.

It can be written as,

(mgsin37 ∘ −μmgcos37 ∘ ) × x= 21 kx²

1×10×(sin37 ∘ −μcos37 ∘ )×(0.1)= 21 ×100(0.1)²

μ=0.127

Thus, the coefficient of friction between the block and the incline is 0.127.

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  • I hope it was helpful to you :)

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