Question

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if

$\frac{1}{x + 2}$
,

$\frac{1}{x + 3}$
and

$\frac{1}{x + 5}$


Are in AP Find value of x.




No irrelevent Answers please ​

Answer 1

Answer:

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$\frac{2}{x + 3} = \frac{1}{x + 2} + \frac{1}{x + 5} (2b = a + c)$

Solve to get , x = 1

Answer 2

$\huge\underline\bold\blue{AnswEr✓}$

$⟹ \frac{2}{x + 3} = \frac{1}{x + 2} + \frac{1}{x + 5}$

$⟹2 \beta = \alpha + c$

⟹ $x=1$