Question

$\huge\mathfrak\color{blue}HELLO$

✨ Please solve the following question✨

If the point C(-2,3) is equidistant from the points A(3,-1) and B(x,8), find the value of x. Also,find the distance BC.

❎ DON'T SPAM❎

$<marquee>{Anushka}</marquee>$

$\huge{Thanks}$​

Answer 1

Given that, C is equidistant from A and B.

i.e. AC = BC

By distance formula,

$\tt \sqrt{ {(3 + 2)}^{2} + {( - 1 - 3)}^{2} } = \sqrt{ {(x + 2)}^{2} + {(8 - 3)}^{2} } \\ \\ \tt \sqrt{ {5}^{2} + {( - 4)}^{2} } = \sqrt{ {x}^{2} + 4 + 4x + {(5)}^{2} } \\ \\ \tt \sqrt{25 + 16} = \sqrt{ {x}^{2} + 4x + 4 + 25} \\ \\ \tt \huge{squaring \: both \: sides} \\ \\ \tt 41 = {x}^{2} + 4x + 29 \\ \\ \tt {x}^{2} + 4x - 12 = 0 \\ \\ \tt{x}^{2} + 6x - 2x - 12 = 0 \\ \\ \tt x(x + 6) - 2(x + 6) = 0 \\ \\ \tt(x - 2)(x + 6) = 0 \\ \\ x = 2 \: or \: - 6$

Answer 2

Answer:

Hey siso...plz inbox me..plz....

can you become my " BIG DIDI " plz...plz inbox me didu....plz