Question

$\huge \mathfrak \color{Green}{\underline{\underline{\colorbox{lightgreen}{Question}} }} :$
A lens form an erect magnified and virtual image of an object and its focal length is 25 cm . Calculate the power of length .​

Answer 1

$\huge \sf \color{Purple}{\underline{\underline{\dag Answer} }} :$

P = +4.0

$\huge \sf \color{Purple}{\underline{\underline{\dag Solution} }} :$

As the lens forms an erect magnified and virtual image of an object it is convex lens .

Focal length of convex lens, f = 25 cm .

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \large f = \frac{25}{100}m => 0.25 m$

$\large \boxed{P = \frac{1}{f(in \ m) }} \\ \\ \implies P = \frac{1}{0.25} \\ \\ \implies P = 0.4 \ D$

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