Physics, asked by Anonymous, 2 months ago

tex] \huge \mathfrak \color{Question}{\underline{\underline{ Question} }} : [/tex]
A lens form an erect magnified and virtual image of an object and its focal length is 25 cm . Calculate the power of length .​

Answers

Answered by TheMist
46

 \huge \sf  \color{Purple}{\underline{\underline{\dag   Answer} }} :

P = +4.0

 \huge \sf  \color{Purple}{\underline{\underline{\dag  Solution} }} :

As the lens forms an erect magnified and virtual image of an object it is convex lens .

Focal length of convex lens, f = 25 cm .

 \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \large f = \frac{25}{100}m => 0.25 m

\large \boxed{P = \frac{1}{f(in \ m) }} \\ \\ \implies P = \frac{1}{0.25} \\ \\ \implies P = 0.4 \ D

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