Physics, asked by OoAryanKingoO79, 5 hours ago

\huge \mathfrak \green{Question}

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Answered by MissDaffodil
2

Average speed :

>> Total distance covered/Total time taken

=> (190 + 190)/(2 + 3)

=> 380/5

=> 76 Km/h

Average velocity :

>> Total displacement covered/Total time taken

Since, the train had returned to its initial position (where it started), so the displacement of the train will be 0 Km.

=> 0/5

=> 0 Km/h

Answers:

=> Average speed of the train is 76 Km/h. => Average velocity of the train is 0 Km/h.

Brainlist please...

Answered by gaurianushka987
2

here is your answer

hope it will help you

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