Question

$\huge \mathfrak \green{Question}$​

Answer 1

Answer:

:

Gɪᴠᴇɴ :

➛ Principle = Rs.8000

➛ Time = 2 years

➛ Rate of Interest = 5% per annum

$\begin{gathered}\end{gathered}$

Tᴏ Fɪɴᴅ :

➛ The amount credited against her name at the end of the second year.

$\begin{gathered}\end{gathered}$

Cᴏᴄᴇᴘᴛ :

↝ Here the concept of Amount has been used. We have given that the Principal is Rs.8000, Time is 2 years and rate is 5 p.c.p.a . We have need to find the Amount.

↝ So, we will find out the Amount by substituting the values in the formula.

$\begin{gathered}\end{gathered}$

Usɪɴɢ Fᴏʀᴍᴜʟᴀ :

$\longrightarrow{\footnotesize{\underline{\boxed{\pmb{\sf{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}}$

Where :-

» A = Amount

» P = Principle

» R = Rate

» T = Time

$\begin{gathered}\end{gathered}$

Sᴏʟᴜᴛɪᴏɴ :

Finding the Amount by substituting the values in the formula :-

${\dashrightarrow{\small{\sf{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg(1 + \dfrac{5}{100}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{(1 \times 100) + (5 \times 1)}{100}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{100 + 5}{100}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{105}{100}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg( \cancel{\dfrac{105}{100}}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg({\dfrac{21}{20}}{\bigg)}^{2}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg({\dfrac{21}{20} \times \dfrac{21}{20}}{\bigg)}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{441}{400} \bigg)}}}}}}$

${\dashrightarrow{\small{\sf{Amount={8000 \times \dfrac{441}{400}}}}}}$

${\dashrightarrow{\small{\sf{Amount={ \cancel{8000} \times \dfrac{441}{\cancel{400}}}}}}}$

${\dashrightarrow{\small{\sf{Amount={ 20 \times 441}}}}}$

${\dashrightarrow{\small{\sf{Amount={Rs.8820}}}}}$

${\longrightarrow{\small{\underline{\boxed{\pmb{\sf{Amount={Rs.8820}}}}}}}}$

• ∴ The amount credited against Maria name at the end of the second year is Rs.8820.

$\begin{gathered}\end{gathered}$

Lᴇᴀʀɴ Mᴏʀᴇ :

$\dashrightarrow{\small{\underline{\boxed{\sf{\purple{ Simple \: Interest = \dfrac{P \times R \times T}{100}}}}}}}$

$\dashrightarrow\small{\underline{\boxed{\sf{\purple{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

$\dashrightarrow\small{\underline{\boxed{\sf{\purple{Amount = Principle + Interest}}}}}$

$\dashrightarrow\small{\underline{\boxed{\sf{\purple{ Principle=Amount - Interest }}}}}$

$\dashrightarrow\small{\underline{\boxed{\sf{\purple{Principle = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}}}}}$

$\dashrightarrow\small{\underline{\boxed{\sf{\purple{Principle = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}$

${\underline{\overline{\rule{200pt}{2pt}}}}$

Answer 2

Answer:

Gɪᴠᴇɴ :

➛ Principle = Rs.8000

➛ Time = 2 years

➛ Rate of Interest = 5% per annum

\begin{gathered}\end{gathered}

Tᴏ Fɪɴᴅ :

➛ The amount credited against her name at the end of the second year.

\begin{gathered}\end{gathered}

Cᴏᴄᴇᴘᴛ :

↝ Here the concept of Amount has been used. We have given that the Principal is Rs.8000, Time is 2 years and rate is 5 p.c.p.a . We have need to find the Amount.

↝ So, we will find out the Amount by substituting the values in the formula.

\begin{gathered}\end{gathered}

Usɪɴɢ Fᴏʀᴍᴜʟᴀ :

\longrightarrow{\footnotesize{\underline{\boxed{\pmb{\sf{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}}⟶

Amount=P(1+

100

R

)

T

Amount=P(1+

100

R

)

T

Where :-

» A = Amount

» P = Principle

» R = Rate

» T = Time

\begin{gathered}\end{gathered}

Sᴏʟᴜᴛɪᴏɴ :

Finding the Amount by substituting the values in the formula :-

{\dashrightarrow{\small{\sf{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}⇢Amount=P(1+

100

R

)

T

{\dashrightarrow{\small{\sf{Amount={8000{\bigg(1 + \dfrac{5}{100}{\bigg)}^{2}}}}}}}⇢Amount=8000(1+

100

5

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{(1 \times 100) + (5 \times 1)}{100}{\bigg)}^{2}}}}}}}⇢Amount=8000(

100

(1×100)+(5×1)

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{100 + 5}{100}{\bigg)}^{2}}}}}}}⇢Amount=8000(

100

100+5

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{105}{100}{\bigg)}^{2}}}}}}}⇢Amount=8000(

100

105

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg( \cancel{\dfrac{105}{100}}{\bigg)}^{2}}}}}}}⇢Amount=8000(

100

105

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg({\dfrac{21}{20}}{\bigg)}^{2}}}}}}}⇢Amount=8000(

20

21

)

2

{\dashrightarrow{\small{\sf{Amount={8000{\bigg({\dfrac{21}{20} \times \dfrac{21}{20}}{\bigg)}}}}}}}⇢Amount=8000(

20

21

×

20

21

)

{\dashrightarrow{\small{\sf{Amount={8000{\bigg(\dfrac{441}{400} \bigg)}}}}}}⇢Amount=8000(

400

441

)

{\dashrightarrow{\small{\sf{Amount={8000 \times \dfrac{441}{400}}}}}}⇢Amount=8000×

400

441

{\dashrightarrow{\small{\sf{Amount={ \cancel{8000} \times \dfrac{441}{\cancel{400}}}}}}}⇢Amount=

8000

×

400

441

{\dashrightarrow{\small{\sf{Amount={ 20 \times 441}}}}}⇢Amount=20×441

{\dashrightarrow{\small{\sf{Amount={Rs.8820}}}}}⇢Amount=Rs.8820

{\longrightarrow{\small{\underline{\boxed{\pmb{\sf{Amount={Rs.8820}}}}}}}}⟶

Amount=Rs.8820

Amount=Rs.8820

∴ The amount credited against Maria name at the end of the second year is Rs.8820.

\begin{gathered}\end{gathered}

Lᴇᴀʀɴ Mᴏʀᴇ :

\dashrightarrow{\small{\underline{\boxed{\sf{\purple{ Simple \: Interest = \dfrac{P \times R \times T}{100}}}}}}}⇢

SimpleInterest=

100

P×R×T

\dashrightarrow\small{\underline{\boxed{\sf{\purple{Amount={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}⇢

Amount=P(1+

100

R

)

T

\dashrightarrow\small{\underline{\boxed{\sf{\purple{Amount = Principle + Interest}}}}}⇢

Amount=Principle+Interest

\dashrightarrow\small{\underline{\boxed{\sf{\purple{ Principle=Amount - Interest }}}}}⇢

Principle=Amount−Interest

\dashrightarrow\small{\underline{\boxed{\sf{\purple{Principle = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}}}}}⇢

Principle=

100+(Time×Rate)

Amount×100

\dashrightarrow\small{\underline{\boxed{\sf{\purple{Principle = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}⇢

Principle=

Time×Rate

Interest×100

{\underline{\overline{\rule{200pt}{2pt}}}}

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Step-by-step explanation:

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