Question

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$\huge\mathfrak\green{question}$


How does an accuracy specified in vol% translates to ppm?
I need to setup some CO2 concentration measurement. The datasheet of the sensor is:

Range: 0 to 25 vol%
Accuracy < 0.5 vol% + 3% of measured value

vol% is the percentage by volume. So the range is: 0 ppm to 250,000 ppm.
Then what is the right reading for accuracy, including an example for the measurement of 400 ppm of CO2 in standard air, let's call it uca for use case accuracy?

0.5 vol% is equal to 5,000 ppm ==> uca = 5,000 ppm + 3% of 400 ppm = 5012 ppm
0.5 vol% is relative to range ==> uca = 0.5% of 250,000 ppm + 3% of 400 ppm = 1262 ppm
something else?​

Answer 1

are bap ra itna bada question bhago Yaha sa

wait let me try it

party do apke new gf ban gaye

hope it's helpful ⤵️

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppm

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.Suppose we have a scale and the data sheets says:

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.Suppose we have a scale and the data sheets says:Range: 0 to 25 kg

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.Suppose we have a scale and the data sheets says:Range: 0 to 25 kgAccuracy < 0.5 kg + 3% of measured value

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.Suppose we have a scale and the data sheets says:Range: 0 to 25 kgAccuracy < 0.5 kg + 3% of measured valueand we measure the value 4kg. The accuracy of this measurement is 0.5kg+3%⋅4kg. Let's transform this logic to your problem: The accuracy is

The volume percentage is a ratio of two volumes. Hence, it is a dimensionless number. The same is true for ppm. Thus, you transform according to1vol%=0.01=0.01⋅106ppm=104ppmas you did. The interpretation is that if you divide the volume in one million parts and select ten thousand of these parts, you selected 1% of all parts. In the following, we will treat vol% as a proper unit, just like m or kg.Suppose we have a scale and the data sheets says:Range: 0 to 25 kgAccuracy < 0.5 kg + 3% of measured valueand we measure the value 4kg. The accuracy of this measurement is 0.5kg+3%⋅4kg. Let's transform this logic to your problem: The accuracy is0.5vol%+3%⋅400ppm=0.5⋅104ppm+3%⋅400ppm=5012ppm