Question

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$\tt{Solve This:-}$
$4 {u}^{2} + 8u$
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$<marquee scrollamount =1500>HilariousHàrshu❤<marquee>$​

Answer 1

Given :-

• 4u² + 8u

To find :-

• Zeros of the given polynomial

Solution :-

→ 4u² + 8u = 0

Take "4u" as a common

→ 4u(u + 2) = 0

Either

→ 4u = 0

→ u = 0

Or

→ (u + 2) = 0

→ u = - 2

Hence,

• Zeros of the given polynomial are 0 and - 2

Extra Information :-

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + b³ + 3ab(a + b)
• (a - b)³ = a³ - b³ - 3ab(a - b)