Question

$\huge \mathfrak \pink{Question.. }$

Be LCM and HCF of two numbers are 4125 and 25 respectively one number is 375 find by how much is a second number less than the first??​

Answer 1

Given: The LCM and HCF of two numbers are 4125 and 24 respectively.

Need to find: How much is a second number less than the first?

❒ Let the first number be 375 and second number be x.

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀

$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀

$\star\; \boxed{\sf{\pink{Product \; of \: two \; numbers = LCM \times HCF}}}$

⠀⠀⠀

Therefore,

⠀⠀⠀

$:\implies\sf 375 \times x = 4125 \times 25 \\\\\\:\implies\sf x = \bigg(\dfrac{4125 \times 25}{375} \bigg) \\\\\\:\implies\sf x = \dfrac{103,125}{375} \\\\\\:\implies{\underline{\boxed{\frak{\purple{x = 275}}}}}\;\bigstar$

⠀⠀⠀

As per given Condition:

⠀⠀⠀

• How much second number is less than the first number.

Therefore,

⠀⠀⠀

$:\implies\sf 375 - 275 = 100$

⠀⠀⠀

$\therefore{\underline{\sf{Hence,\; second\; number\; is \; less \; than \; the \: first \; number\: by\; \bf{100 }.}}}$

Answer 2

Answer:

here is ur answer

hope it is correct..