Math, asked by ⲊⲧɑⲅⲊⲏɑᴅⲟᏇ, 10 hours ago

\huge\mathfrak{Prove:}
\bf{\frac{d( \ { \sin}^{n}x . \cos \: n  \: x ) }{dn}  = n \:  { \sin }^{n + 1}  \:  \cos( n + 1)x}

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Answered by ᴠɪʀᴀᴛ
1

\huge\bf\underline{\underline{\pink{A} \orange{N}\blue{S}\red{W}\green{E} \purple{R}}}

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Answered by AthulyaAnjana
1

Answer:

This is the answer

Step-by-step explanation:

Hopes it's correct have a nice day

Good evening in advance

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