Question

$\huge\mathfrak \purple{Question:-}$



To do a certain work, A and B work on altemate days with B beginning the work on the first day. A alone the same work in 24 days. If the work gets completed in 11 days, then B alone can complete th part of the original can complete work.

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Answer 1

Step-by-step explanation:

given :

• certain work of A and B = 24 days

• complete work = 11 days

to find :

• original can complete work = ?

• original can complete work = ?

solution :

A work for one day = 1/48

B work for one day = 1/9

• = 1/9 + 6 days for complete for B

we take the B complete work = a

• 8/9 = 6/a

• = 27/4

days 4 time complete certain work

• = 4×27/4

orginal part to completed = 27 days

Answer 2

${ \boxed{\mathbb{\red{⛄answer♡࿐⛄}}}}$

${ {\mathbb{\pink{27 \: days}}}}$

$\underline{ \boxed{\mathbb{\orange{⛄solution \: step \: by \: step \: explanation♡࿐⛄}}}}$

• .Let the efficiency of A be 1 unit
• Total work = 48 x 1 = 48 units
• Working alternatively,
• Time for which A work in days = days
• Work done by A = units
• Time for which B work = 6 days
• Work done by B = 48 - = units
• Efficiency of B = 128/18 units per day
• Time taken by B to finish 4 times the work = 192/(128/18) = 27 days

Hope it helpful for you