Question

$\huge\mathfrak {Question:}$


Calculate the number of neutrons present in the nucleus of an element X which is represented as 15^31X.


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Answer 1

$\huge \rm \red{answer: - }$

16 Neutrons.

$\fbox {given: - }$

Element = x

Mass number of element = 31

Number of electrons in the element = 15

$\fbox{to \: find: - }$

Number of neutrons in the element

$\fbox {formula: - }$

Mass number:- Number of protons+Number of Neutrons.

$\fbox{finding: - }$

31:- 15+x

31-15 = x

x:- 16

Answer 2

Here, atomic number =15=electrons=protonsMass Number = 31Number of neutrons + number of protons= Atomic mass number.∴ Number of neutrons =31−number of protons=31−15=16

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