Question

$\huge \mathfrak{question}$
⤵⤵

CLASS 11
CHEMISTRY

If a mole were to contain
$1.00 \times {10}^{24}$
particles what would be the mass of
(i) a single oxygen molecule
(ii) one mole of oxygen

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Answer 1

Answer: single oxygen molecule mass =

1 = 32x1.66x10^-24 g =

26.56 x10^-24 GM. = 53.12 x10^-24gm

Explanation:

1 mole oxygen mass =

32amux1x10^24

32X 1.66x10^-24x10^24 gm

53.12gm

Answer 2

As we are aware that 1 avagadro number contains $\implies{\mathsf{ = 6.022 \times 10^{23}particles}}$

But, According to question

It it is given that a mole contains $\implies{\mathsf{ = 1 \times 10^{24}particles}}$

To find :

(i) a single oxygen molecule

$\implies{\mathsf{ Mass \: of \: O_2(oxygen)\: molecule }}$

As we are aware that Mass of 1Na oxygen molecule is $\implies{\mathsf{Na \times \frac{1}{32}}}$

$\implies{\mathsf{Na \times \frac{1}{32}}}$

= 0.03125 Na

$\implies{\mathsf{1 \times 10^{24} \times \frac{1}{32}}}$

$\implies{\mathsf{1 \times 10^{24} \times 0.03125}}$

$\implies{\mathsf{= 3.125 \times 10^{22}gm}}$

(ii) one mole of oxygen atom

1 mole = 1 ÷ Na` [given in question]

To find mass of 1 mole of oxygen is 1 × 1/16 = $\implies{\mathsf{1 \times 10^{24} \times \frac{1}{16}}}$

= 6.25 × 10^(22)gm