Question

$\huge \mathfrak \red{Question}$​

Answer 1

Answer:

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Given :

• . A vehicle starts to move from rest and accelerates at the rate of 0.5 m/s².

To Find:

• • Final Velocity and Distance travelled by the vehicle in 4 minutes.

Solution :

• → Initial Velocity (u)-0 m/s
• Time Taken (t) = 4 min = 240 sec
• → Acceleration (a):0.5 m/s²

Using 1st Equation :

v = u + at

Putting Values:

➔ v = 0+0.5 x 240

➔ v = 0+120

➔ v = 120 m/s

So, The Final Velocity is 120 m/s.

For Distance:

Using 3rd Equation :

v² - u²= 2as

Putting Values:

➙ 120² - 0² = 2 × 0.5× s

➙ 14400 = 1s

➙ s =14400 m

So, The Distance covered by the vehicle is 14400 m

Answer 2

Answer:

Given :

A car has an constant acceleration of 4 m/s² , starting from rest it reaches the speed of 40 m/s.

To Find :

Distance travelled by the car .

Solution :

$\longmapsto\tt{Initial\:Velocity\:(u)=0\:m/s}$

$\longmapsto\tt{Final\:Velocity\:(v)=40\:m/s}$

$\longmapsto\tt{Acceleration\:(a)=4\:{m/s}^{2}}$

For Time :

Using 1st Equation :

$\longmapsto\tt\boxed{v=u+at}$

Putting Values :

$\longmapsto\tt{40=0+4\:t}$

$\longmapsto\tt{40=4\:t}$

$\longmapsto\tt{\cancel\dfrac{40}{4}=t}$

$\longmapsto\tt\bf{10\:sec=t}$

Now ,

For Distance Travelled :

Using 2nd Equation :

$\longmapsto\tt\boxed{s=ut+\dfrac{1}{2}\:{at}^{2}}$

Putting Values :

$\longmapsto\tt{0\times{10}+\dfrac{1}{2}\times{4}\times{(10)}^{2}}$

$\longmapsto\tt{0\times{10}+\dfrac{1}{{\not{2}}}\times{{\not{4}}}\times{100}}$

$\longmapsto\tt{0+2\times{100}}$

$\longmapsto\tt\bf{200\:m}$

• So , The Distance Travelled by the car is 200 m .