Question

$\huge \mathfrak \red{Question}$
Calculate the heat produced when 96000 coulombs of charge is transferred in 1 hour through a potential difference of 50 volts.


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Answer 1

Answer:

The heat produced is 4800 kJ.

Explanation:

We have given that,

• Charge transferred ( Q ) = 96000 coulombs

• Time ( t ) = 1 hour = 60 min = ( 60 * 60 ) s = 3600 s

• Potential difference ( V ) = 50 volts

We have to find the heat produced.

Now, we know that,

$\displaystyle{\pink{\sf\:Heat\:produced\:=\:V\:I\:t}}$

$\displaystyle{\implies\sf\:H\:=\:V\:\times\:\dfrac{Q}{\cancel{t}}\:\times\:\cancel{t}\:\quad\:\dots\:\left[\:\because\:I\:=\:\dfrac{Q}{t}\:\right]}$

$\displaystyle{\implies\sf\:H\:=\:V\:\times\:Q}$

$\displaystyle{\implies\sf\:H\:=\:50\:\times\:96000}$

$\displaystyle{\implies\sf\:H\:=\:48000\:\times\:2\:\times\:50}$

$\displaystyle{\implies\sf\:H\:=\:48000\:\times\:100\:J}$

$\displaystyle{\implies\sf\:H\:=\:\dfrac{48\cancel{000}}{1\cancel{000}}\:\times\:100\:kJ}$

$\displaystyle{\implies\sf\:H\:=\:48\:\times\:100\:kJ}$

$\displaystyle{\implies\sf\:H\:=\:4800\:kJ}$

$\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:Heat\:produced\:=\:4800\:kJ}}}}$

∴ The heat produced is 4800 kJ.