Question

$\huge\mathfrak{\underline{Question:}}$
An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s². The takeoff speed for this plane will be 65 m/². Assuming this minimum acceleration, what is the minimum allowed length for the runway?
​

Answer 1

${\large{\pink{➢{\blue{\underline{\orange{\textbf{Question :}}}}}}}}➢$

An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s². The takeoff speed for this plane will be 65 m/². Assuming this minimum acceleration, what is the minimum allowed length for the runway?

■■■■■■■■■■■■■■■■■■■■

☞Given :-

initial velocity, u=0m/s and final velocity v=65m/s

■■■■■■■■■■■■■■■■■■■■■■■■

Acceleration a=3m/s²

If d be the allowed length for the runway.

Using formula v² −u² =2aS

(65)² −0² =2(3)d

⟹ d=65 2 /6=704.16∼704m

■■■■■■■■■■■■■■■■■■■■

• I hope it was helpful to you : )

$\mathfrak \red{BeBrainly}$

Answer 2

$\huge\mathfrak{\underline{Question:}}$

An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s². The takeoff speed for this plane will be 65 m/². Assuming this minimum acceleration, what is the minimum allowed length for the runway?

Answer:

Given, initial velocity, u=0m/s and final velocity v=65ms

Acceleration a=3m/s²

If d be the allowed length for the runway.

Using formula v² −u² =2aS

(65) ² −0 ² =2(3)d

⟹ d=65 ²/6=704.16∼704m