A 400 kg Satellite is a circular orbit of radius 2RE about the Earth. How much energy is required to transfer it to a circular orbit of radius 4RE ?
What are the Changes in the Kinetic and potential energy....
Answers
Answered by
4
Explanation:
M1=6×10^24 kg
M2=400 kg
Re=6.4×10^6 m
G=6.67×10^-4 Nm^2/ kg
GM1 M2 = 6.67×10^11×6×10^24×400
2(2Re 2×12.8×10^6
= 6.25=10^9 J
K.E= 6.25×10^9 J
P.E= -2 K.E = -12.5×10^9 J
T.E = P.E+ K.E
= 6.25×10^9 J
Hope it helps you my friend.......
Similar questions