Question

$\huge\mathtt{\color{goldenrod}{Question:-}}$

$\implies$ There is a square field of side 60m each . A house is to be constructed in the middle of field and a garden is to be developed in the remaining part of the field . if the dimensions of the house are 45 x 25m , Find the area of the garden.

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Answer 1

${\huge{\underbrace{\rm{Answer\checkmark}}}}$

$\longrightarrow \rm \: area \: of \: garden \: = area \: of \: square \\ \rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - \: area \: of \: house$

$\implies \: 60 \times 60 - 45 \times 25 \: {m}^{2}$

$\implies \: 3600 - 1125 \: {m}^{2}$

$\implies \: \rm 2475 {m}^{2}$

Answer 2

$\huge{ { \underbrace{ \mathbb{ \red{Question\ }}}}}$

There is a square field of side 60m each. A house is to be constructed in the middle of field and a garden is to be developed in the remaining part of the field. If the dimensions of the house are 45 x 25m, Find the area of the garden.

${\tt{\green{\underline{\underline{\huge{Answer}}}}}}$

Area of the square field = 60 × 60 = 3600 sq m

Area of the house to be constructed = 45 × 25 = 1125 sq m

The remaining Area in which lies the garden = 3600 - 1125 = 2475 sq m.(Answer)

$\huge \fbox \pink {Hope \: it \: helps \: you}$