Question

$\huge\mathtt\pink{QUESTION}$

In a right triangle ABC, right angled at B, find AC,
if (i) AB = 10 cm. BC = 24 cm
(ii) AB = 7 cm, BC = 24 cm​

Answer 1

$\huge\mathtt\pink{ANSWER}$

Given :

A right triangle ABC, right angled at B .

(i) AB = 10 cm. BC = 24 cm .

(ii) AB = 7 cm, BC = 24 cm .

To Find :

Length of AC .

Solution :

(i) AB = 10 cm. BC = 24 cm :

Using Pythagoras Theorem :

$\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\longmapsto\tt{{(AC)}^{2}={(10)}^{2}+{(24)}^{2}}$

$\longmapsto\tt{{AC}^{2}=100+576}$

$\longmapsto\tt{{AC}^{2}=676}$

$\longmapsto\tt{AC=\sqrt{676}}$

$\longmapsto\tt\bf{AC=26\:cm}$

(ii) AB = 7 cm, BC = 24 cm :

Using Pythagoras Theorem :

$\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\longmapsto\tt{{(AC)}^{2}={(7)}^{2}+{(24)}^{2}}$

$\longmapsto\tt{{AC}^{2}=49+576}$

$\longmapsto\tt{{AC}^{2}=625}$

$\longmapsto\tt{AC=\sqrt{625}}$

$\longmapsto\tt\bf{AC=25\:cm}$

Hope it helps :)

____________

XxMrQatilxX ✅

Answer 2

Ans lelo

btw good evening shivu