Question

$\huge\mathtt\pink{QUESTION}$

In a right triangle ABC, right angled at B, find AC,
if (i) AB = 10 cm. BC = 24 cm
(ii) AB = 7 cm, BC = 24 cm​

Answer 1

Answer:

1)26cm

2)25cm

Step-by-step explanation:

Answer 2

(i) AB = 10 cm. BC = 24 cm

Given:

• A right triangle ABC, right angled at B .
• (i) AB = 10 cm. BC = 24 cm .

To Find:

• Length of AC = ?

Solution:

we know that,

★ (i) AB = 10 cm. BC = 24 cm :

by Using Pythagoras Theorem :

$\\\sf\dashrightarrow{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\sf\dashrightarrow{{(AC)}^{2}={(10)}^{2}+{(24)}^{2}}$

$\sf\dashrightarrow{{AC}^{2}=100+576}$

$\sf\dashrightarrow{{AC}^{2}=676}$

$\sf\dashrightarrow{AC=\sqrt{676}}$

$\sf\dashrightarrow{AC=26\:cm}$

${\bigstar{\red{\underline{\boxed {\sf{AC=26\:cm}}}}}}$

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(ii) AB = 7 cm, BC = 24 cm :

Given:

• In a right triangle ABC, right angled at B, find AC,
• (ii) AB = 7 cm, BC = 24 cm

To Find:

• Length of AC = ?

Solution:

we know that,

(ii) AB = 7 cm, BC = 24 cm :

by Using Pythagoras Theorem :

$\\\sf\dashrightarrow{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}$

$\sf\dashrightarrow{{(AC)}^{2}={(7)}^{2}+{(24)}^{2}}$

$\sf\dashrightarrow{{AC}^{2}=49+576}$

$\sf\dashrightarrow{{AC}^{2}=625}$

$\sf\dashrightarrow{AC=\sqrt{625}}$

$\sf\dashrightarrow{AC=25\:cm}$

${\bigstar{\red{\underline{\boxed {\sf{AC=25\:cm}}}}}}$

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