Question

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Answer 1

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Answer 2

$\huge\mathtt\pink{Answer}$

$\frac{3 - \sqrt{6} }{3 + 2 \sqrt{6} } = a \sqrt{6} - b$

$→ \frac{3 - \sqrt{6} }{3 + 2 \sqrt{6} } \times \frac{3 - 2 \sqrt{6} }{3 - 2 \sqrt{6} } = a \sqrt{6} - b$

$→ \frac{9 - 6 \sqrt{6} - 3 \sqrt{6} + 12}{(3) -(2 \sqrt{6} )} = a \sqrt{6} - b$

$→ \frac{21 - 9 \sqrt{6} }{9 - 27} = a \sqrt{6} - b$

$→ \frac{21 - 9 \sqrt{6} }{ - 15} = a \sqrt{6} - b$

$→ \frac{9}{15} \sqrt{6} - \frac{21}{15} = a \sqrt{6} - b$

$→ \frac{3}{5} \sqrt{6} - \frac{7}{5} = a \sqrt{6} - b$

$→9 = \frac{3}{5} \\ b = \frac{7}{5}$

$\huge\mathtt\red{Formula}$

$★(a + b)(a - b) = (a - b)★$