Question

$\huge\orange{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{Hey\:Mate}}}}}}}$

How to solve the above question??

${\mathbb{\underline{\huge{\pink{\fbox{Explanation\:required}}}}}}$

#Mathematics Genius only
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Answer 1

Answer:

a + b = 29 ----(1)

b + c = 45 ---(2)

a + c = 44 -----(3)

adding eq (1) , (2) and (3)

a + b + b + c + a + c = 29 + 45 + 44

2a + 2b + 2c = 118

2 ( a + b + c ) = 118

a + b + c = 118 / 2

a + b + c = 59

a + b + c = 59

hope it helps

Answer 2

Given,

• a + b = 29
• b + c = 45
• a + c = 44

To Find,

• Value of a + b + c

Solution :

$\implies$ Give three Equation in this Question :-

• a + b = 29   1) Equation
• b + c = 45     2) Equation
• a + c = 44     3) Equation

║Now Add All this three Equation║

$\implies \sf{\therefore (a +b) + (b+c) +(a +c) = 29 + 45 + 44}$

$\implies \sf{2a + 2b + 2c = 118}$

$\implies \sf{2(a + b + c) = 118}$

$\implies \sf{a + b + c = \dfrac{118}{2}}$

$\implies \boxed{\sf{\pink{a + b + c = 59}}}$

$\rule{200}2$

$\hugeP{\bf{\underline{\red{Other \ Method \ to \ Find :}}}}$

Firstly we Add the Equation First and Third :-

∴a + b = 29

(-)a +(-)c = (-)44

                   

b - c = -15

∴b = 15 + c

Now Put the Value of b in Second Equation :-

∴ b + c = 45

⇒-15 + c + c = 45

⇒2c = 45 + 15

⇒2c = 60

⇒c = 30

Therefore,

⇒ b = 15 + c

⇒b = 15 + 30

⇒b =  45

Now Put the value of b in First Equation :-

⇒a + b = 29

⇒a + 45 = 29

⇒a = 29 - 45

⇒a = -16

Therefore,

$\implies \sf{a + b + c = ?}$

$\implies \boxed{\sf{-16 + 45 + 30 = 59}}$

$\rule{200}2$