Math, asked by 1Angel25, 8 months ago

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Which of these equation is INCORRECT ?

(a) \: \sqrt{16} \: + \: \sqrt{3} \: = \sqrt{16 + 3} \\ \\ (b) \: \sqrt{6} \: \times \sqrt{12} \: = \sqrt{6 \times 12} \\ \\ (c) \: neither \: is \: incorrect \\ \\ (d) \: both \: are \: incorrect

Answers

Answered by debanshbiswal2538
3

Step-by-step explanation:

 \sqrt{16}  +  \sqrt{3}  =  \sqrt{16 + 3}  \\

It is incorrect because the sum of root over of 16 and with that of root over 3 will gives 5.7 approximately but whole root of 16+13 will give 5.4 approximately. so this equation is incorrect

Answered by jaishankarverma62
1

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It is incorrect because the sum of root over of 16 and with that of root over 3 will gives 5.7 approximately but whole root of 16+13 will give 5.4 approximately. so this equation is incorrect

\begin{lgathered}\sqrt{16} + \sqrt{3} = \sqrt{16 + 3} \\\end{lgathered}

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