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at what rate % will ruppees 400 amount to ruppes 441 in 1 year when intrest is compounded half early..??
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Given :-
A = p(1+(r/m))^(m^n)
M = 2
N = 1 year
A = 441
P = 400
To find :-
441 = 400 (1+r/2)²
441/400 = (1+((r/2))²
21²/20² = (r+r/2)²
Solution :-
(21/20)² = (r+r/2)²
(1+1/20)² = (r+r/2)²
1+1/20 = r+r/2
r/2 = 1/20
r = 1/10 = 0.1/1.100% = 10%
Hence,
- Rate is 10%
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