Question

$\huge \pink {answer}$


Ques-: Rock under is 2900m deep. Calculate the time in which an ultrasonic sign will return from reflection from the rocks. take velocity of ultrasonic in water as 1.45 km/s.


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Answer 1

$\huge{\boxed{\boxed{\underline{\mathfrak{Answer \ :}}}}}$

$\underline{\underline{\bf{Given \ :}}}$

• x = 2900 m, where x is the distance if the rock the surface of the water.

• v = 1.45 km/s = 1450 $\sf{ms^{-1}}$, where v is the speed of ultrasonic waves in water.

$\underline{\underline{\bf{To \ Find \ :}}}$

We have to find the value of t which is the time in which an ultrasonic signal return from the rock.

$\underline{\underline{\bf{Explanation :}}}$

We know that,

$\large{\boxed{\boxed{\rm{x = \frac{v \times t}{2}}}}}$

_______________[Putting Values]

$\sf{ \implies 2900 = \frac{1450 \times t}{2}} \\ \\ \sf{ \implies t = \frac{2 \times \cancel{2900}}{\cancel{1450}}} \\ \\ \sf{ \implies t = 2 \times 2} \\ \\ \sf{t = 4}$

$\large{\boxed{\boxed{\bf{Answer \ : 4 \ seconds }}}}$