How many terms of the AP -1,-5,-9 must be taken to get a sum of -496
Answers
Answered by
46
How Many terms of the A.P.
-1 , -5 , -9 , . . . should be taken to get a Sum of -496.
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An A.P. -1 , -5 , -9 , . . .
So,
First term = a = -1
And
Common difference = d = -4
Let Required Number of turns be = n
So,
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Value of n
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Sum of n terms if an A.P is given by :
___________________________
We have,
a = -1
d = -4
Sum = -496
Applying Formula of Sum ,
As n is number of terms so it can't be Negative.
Hence ,
___________________________
Answered by
63
Answer:
Given :-
- The AP of - 1, - 5, - 9 must be taken to get a sum of - 496.
To Find :-
- How many numbers of terms can be found in an AP.
Formula Used :-
Sum of first n terms of an AP Formula :
where,
- = Sum of first n terms of an AP
- a = First term of an AP
- d = Common difference
- n = Number of terms of an AP
Solution :-
Given :
According to the question by using the formula we get,
The number of terms can be found in an AP is 16.
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EXTRA INFORMATION :-
General term (nth term) of an AP Formula :
where,
- = nth term of an AP
- a = First term of an AP
- n = Number of terms of an AP
- d = Common difference
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