Question

$\huge \pink{ \mathbb{HEY : }}$

Que :- a lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior the diameter of pencil is 7 mm and the diameter of graphite is 1 mm if the length of the penis size is 14 cm find the volume of wood.

$\large \pink{ \underline{\pink{ \boxed{\pink{ \mathbb{HAVE \: A \: NICE \: DAY :) }}}}}}$
​

Answer 1

Step-by-step explanation:

Question :-

A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior the diameter of pencil is 7 mm and the diameter of graphite is 1 mm if the length of the penis size is 14 cm find the volume of wood.

Answer

We have to find the volume of the pencil.

${{{ \purple{\bf Radius \: of \: the \: pencil \: = \frac{7}{2} mm }}}} \\ { \purple{\bf \: Height \: of \: the \: pencil \: = 14 cm = 140mn}}$

${ \red{\bf \: Volume \: of \: the \: pencil \: = \frac{22}{7} \times ( \frac{7}{2} )^ 2 \times 140 } } \\ { \red{ \bf=5390mm^ 3}}$

Now finding the volume of the graphite.

${ \blue{ \bf \: Radius \: of \: the \: dite= \frac{ 1}{ 2} mm}}$

${ \bf \blue{ Volume \: of \: the \: phite \: = 2 \frac{22}{7} \times ( \frac{1}{2} )^ 2 \times 140}} \\ { \blue{\bf=110mm^ 3}}$

Now finding the volume of the wood.

$\pink{ \bf \: Volume \: of \: the \: wood \: = Volume \: of \: the \: pencil \: - Volume \: of \: the \: graphite \:} \\ \pink{\bf=(5390-110)mm^ 3 }\\ \pink{\bf =5280mm^ 3}$

$\boxed{ \green{\bf \: Volume \: of \: the \: wood \: is \: 5280 m ^ 3 and \: the \: volume \: of \: the \: graphite \: is \: 110mm³.}}$

Answer 2

Answer:

Volumeofthepencil=

7

22

×(

2

7

)

2

×140

=5390mm

3

Now finding the volume of the graphite.

{ \blue{ \bf \: Radius \: of \: the \: dite= \frac{ 1}{ 2} mm}}