Math, asked by hritikrbahadur, 10 months ago


 \huge{ \pink{ \mathfrak{ \blue{hlo \: mate}}}}

The paint in a certain container is sufficient to paint an area of equal to 9.375 metre square. How many bricks of dimensions 22.5cm×10cm×7.5cm can be painted out of this container.​

Answers

Answered by Anonymous
41

 \huge{ \mathtt{ \purple{SOLUTION:-}}}

Number of the bricks that can be painted out of the container = Area that can be painted by the container/surface area of brick

Area that can be painted by the container =9.375m^2

 \large{ \implies{9.375 \times  {100}^{2}  {cm}^{2} }}

 \large{ \implies{9.375 \times 10000 {cm}^{2} }}

 \large{ \implies{93750 {cm}^{2} }}

Total surface area of one brick = 2(lb+bh+hl)

 \small{ \implies{2(22.5 \times 10  + 10 \times 7.5 + 22.5 \times 7.5) {cm}^{2} }}

 \small \implies{2(22.5 + 75 + 168.75) {cm}^{2} }

\small \implies{(2 \times 468.75) {cm}^{2} }

\small \implies{ \bold{937.5 {cm}^{2} }}

No. of bricks that can be painted out of the container = Area that can be painted by the container/surface area of the brick

 \large{ \implies{ \frac{93750}{937.5}}}

\large{ \implies{ \frac{937500}{9375}}}

\large{ \implies{ \bold{100}}}

Therefore,

100 bricks can be painted out by the paint.

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