Question

$\huge\pink{\mid{\fbox{\tt{Question}}\mid}}$

A positive number is 5 time another number. If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers. Find the original numbers.​

Answer 1

Given :

• A positive number is 5 times another number.
• If 21 is added to both the numbers, then one of the numbers become twice of other new numbers.

To Find :

• The original numbers.

Solution :

Let's assume the other number as x.

Given that, a positive number is 5 times another number, so the positive number would be :

$\longmapsto \: \: \: \tt \: 5x$

A.T.Q :

$\longmapsto \: \: \: \: \tt \: 5x + 21 = 2x + 42$

Transposing 2x to L.H.S & 21 to R.H.S and performing subtraction,

$\longmapsto \: \: \: \: \tt \: 5x - 2x = 42 - 21 \\ \\ \longmapsto \: \: \: \tt \: 3x = 21$

Now taking out the value of x,

$\longmapsto \: \: \: \: \tt \: x = \cancel\dfrac{21}{3}$

On dividing,

$\longmapsto \: \: \: \: \large\underline{ \boxed{ \tt{ \purple{x = 7}}}}$

So,

• Other Number :

$\implies \bf \: x = 7$

• Positive Number :

$\implies \bf \: 5x = 5 \times 7 \\ \implies \bf \: 35$

$\therefore \: \underline{ \sf{Original \: numbers \: are \: \pmb 7 \: \& \: \pmb{35}}} \: .$

Answer 2

open the attachment

I hope it will help you