Question

$\huge \pink{question}$

$if \frac{ {cos}^{2} teta}{sin \: teta} = p \: and \: \frac{ {sin}^{2}teta }{cos \: teta} = q \: then \\ \\ prove \: that \: {p}^{2} {q}^{2}( {p}^{2} + {q}^{2} + 3) = 1$
❥ Need a correct answer ☺️​

Answer 1

Answer:

$\huge\mathfrak\blue{answer}$

LHS :

q(p

2

−1)

=(secθ+cosec θ)[(sinθ+cosθ)

2

−1]

=(

cosθ

1

+

sinθ

1

)(2sinθcosθ)

=(

sinθcosθ

sinθ+cosθ

)(2sinθcosθ)

=2(sinθ+cosθ)=2p = RHS

hope it helps you ☺️

Answer 2

Answer:

q(p

2

−1)

=(secθ+cosec θ)[(sinθ+cosθ)

2

−1]

=(

cosθ

1

+

sinθ

1

)(2sinθcosθ)

=(

sinθcosθ

sinθ+cosθ

)(2sinθcosθ)

=2(sinθ+cosθ)=2p = RHS