Question

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Answer 1

Answer:

44.

=> $x^2 - (2b-1)x + (b^2 - b - 20) = 0$

=> $x^2 - (2b-1)x + (b^2 - 5b + 4b - 20) = 0$

=> $x^2 - (2b-1)x + ( b(b-5)+ 4(b - 5) ) = 0$

=> $x^2 - (2b-1)x + (b-5)(b+4) = 0$

=> $x^2 - (b-5 + b+4)x + (b-5)(b+4) = 0$

=> $x^2 - (b-5)x - (b+4)x + (b-5)(b+4) = 0$

=> $x (x-b+5) - (b+4)(x-b+5) = 0$

=> $(x-b-4)(x-b+5) = 0$

=> $<strong>x = b + 4</strong><strong>. </strong><strong>;</strong><strong> </strong><strong> x = b - 5. </strong>$

45.

=> $x^2 + 6x - (a^2 + 2a - 8) = 0$

=> $x^2 + 6x - (a^2 + 4a - 2a - 8) = 0$

=> $x^2 + 6x - ( a(a+4) -2(a+4) ) = 0$

=> $x^2 + 6x - (a+4)(a-2) = 0$

=> $x^2 + 6x + (a+4)(2-a) = 0$

=> $x^2 + (a+4+2-a)x + (a+4)(2-a) = 0$

=> $x^2 + (a+4)x + (2-a)x + (a+4)(2-a) = 0$

=> $x (x+a+4) + (2-a)(x+a+4) = 0$

=> $(x+a+4)(x+2-a) = 0$

=> $<strong> </strong><strong>x</strong><strong> </strong><strong>=</strong><strong> </strong><strong>-</strong><strong>(</strong><strong>a</strong><strong> </strong><strong>+</strong><strong> </strong><strong>4</strong><strong>)</strong><strong> </strong><strong>;</strong><strong> </strong><strong>x</strong><strong> </strong><strong>=</strong><strong> </strong><strong>a</strong><strong> </strong><strong>-</strong><strong> </strong><strong>2</strong><strong>. </strong>$

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