Question

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If g is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is​

Answer 1

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Explanation:

Answer 2

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Acceleration due to gravity on surface of

Acceleration due to gravity on surface ofearth=g

Acceleration due to gravity on surface ofearth=gLet

Acceleration due to gravity on surface ofearth=gLetRadius of earth=R

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Value of acceleration due to gravity at height equal to double the radius of earth.

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Height,h=2R

Acceleration due to gravity on the surface of earth,g

$= \frac{gm}{r2}$

When h=2R

When h=2RThen, the value of acceleration due to gravity.

$g' = \frac{gm}{(2r)2}$

$g' = \frac{gm}{4r(2)}$

$g' = \frac{1}{4} g$