Question

$\huge{Question}$​

Answer 1

Answer:

Given :

The display of the square board is 80 cm. The cost of ribbon is Rs.11 per m.

$\rule{200pt}{3pt}$

To Find :

Cost of ribbon needed to put around the display board .

$\rule{200pt}{3pt}$

Solution :

✏ Formula Used :

$\large{\color{cyan}{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Perimeter{\small_{(Square)}} = 4 \times Side }}}}}$

$\qquad{\rule{150pt}{1pt}}$

✏ Calculating the Perimeter :

${\longmapsto{\qquad{\sf{ Perimeter{\small_{(Display \: Board)}} = 4 \times Side }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Perimeter{\small_{(Display \: Board)}} = 4 \times 80 }}}} \\ \\ \ {\qquad{\textsf{ Perimeter of the Display board = {\red{\sf{ 320 \: cm }}}}}}$

$\qquad{\rule{150pt}{1pt}}$

✏ Calculating the Cost :

${\dashrightarrow{\qquad{\sf{ Cost = Perimeter \times Rate }}}} \\ \\ \ {\dashrightarrow{\qquad{\sf{ Cost = \dfrac{320}{100} \times 11 }}}} \: \: \: \: {\qquad {\pink{\bigg\lmoustache{\underline{\green{\sf{ 100 \: cm = 1 \: m }}}} \bigg\rmoustache}}} \\ \\ \ {\dashrightarrow{\qquad{\sf{ Cost = \cancel\dfrac{320}{100} \times 11 }}}} \\ \\ \ {\dashrightarrow{\qquad{\sf{ Cost = 3.20 \times 11 }}}} \\ \\ \ {\qquad{\sf{ Cost \: of \: Ribbon \: = {\blue{\sf{ ₹ \: 35.2 }}}}}}$

$\qquad{\rule{150pt}{1pt}}$

✏ Therefore :

❝ Cost of applying the ribbon around the Display board is ₹ 35.2 . ❞

$\\ {\underline{\rule{200pt}{9pt}}}$

Answer 2

$\huge\sf\fbox\purple{ ★ Solution ★}$

°°° Explanation °°°

To find zero of the polynomial, p(x)=0

(i) If p(x)=x+5=0 then x=−5, i.e. −5 is the zero.

(ii) If p(x)=x−5=0 then x=5, i.e. 5 is the zero.

(iii) If p(x)=2x+5=0 then x= 2

−5 , i.e. 2−5 is the zero.

(iv) If p(x)=3x−2=0 then x= 32

, i.e. 32 is the zero.

(v) If p(x)=3x=0 then x=0, i.e. 0 is the zero.

(vi) If p(x)=ax=0 then x=0, i.e. 0 is the zero.

(vii) If p(x)=cx+d=0 then x= c−d

, i.e. c −d

is the zero.