Question

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The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically and geometrically?.




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Answer 1

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically and geometrically?.

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Answer 2

QuestioN :

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically and geometrically?.

GiveN :

• 2 kg apple + 1kg grapes per day cost = Rs.160
• 4 kg apples + 2kg grapes per day cost = Rs.300

To FiNd :

• Represent the situation algebraically and geometrically?.

SolutioN :

x 65  55  45  35

y 20  40  60  80

Let the cost of 1 kg of apples be x and that of 1 kg be y.

So the algebraic representation can be as follows:

2x+y=160

4x + 2y = 300 ⇒ 2x + y = 150

The situation can be represented graphically by plotting these two equations.

2x + y = 160 ⇒ y = 160 − 2x

x              70 60 50 40

y = 160 − 2x   20  40  60  80

2x + y = 150 ⇒ y = 150 − 2x

x              65 55 45 35

y = 150 − 2x   20  40  60  80

We can see that the lines do not intersect anywhere, i.e. they are parallel. Hence we can not arrive at a solution.