Question

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➳ REQUIRED GOOD ANSWER​

Answer 1

Answer:

$f(x) = \frac{2x + 1}{x - 1}$

.

$f( {x}^{ - 1} ) = \frac{2 {x}^{( - 1)} + 1 }{ {x}^{( - 1)} - 1} \\ \\ = > f( \frac{1}{x} ) = \frac{ \frac{2}{x} + 1}{ \frac{1}{x} - 1} \\ \\ = > f( {x}^{ - 1} ) = \frac{2 + x}{1 - x}$

Answer 2

$\sf \color{blue}{\bigstar}$ $\Large \sf \color{red}{Answer :}$

→ It is given to solve the and find the given pairs of equation — f(x) = $\frac{2x + 1}{x - 1}$,

Follow the steps...

$\Rightarrow$ f(x) = $\frac{2x + 1}{x - 1}$

$\Rightarrow$ f($x^{-1}$) = $\frac{2x^{(-1)} + 1}{x^{(-1)} - 1}$

$\Rightarrow$ f($\frac{1}{x}$) = $\frac{\frac{2}{x} + 1}{\frac{1}{x} - 1}$

$\Rightarrow$ f(x - 1) = $\frac{2 + x}{1 - x}$

Hope it help uh! :)