Question

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To fill a swimming pool two pipes are to be used. If the pipe of larger diameter is used for 4 hours and the pipe of smaller diameter for 9 hours, only half the pool can be filled. Find, how long it would take for each pipe to fill the pool separately, if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool?







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Answer 1

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No need of marking me brainliest:-)

Answer 2

Heya!

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According to question, 2 pipes are used to fill a swimming pool.

Pipe with larger diameter is used for 4 hours and pipe with smaller diameter is used for 9 hours.

Let x hours be the total time taken by the larger pipe to fill the tank

so in 1 hour it would fill

$\frac{1}{x}$

part of the tank.

Similarly, y hours are needed for the smaller pipe, then 1 hour it would fill

$\frac{1}{y}$

part.

So, y = 10+x ...(1)

$\frac{4}{x} + \frac{9}{y} = \frac{1}{2}$

$using (1), \frac{4}{x} + \frac{9}{10 + x} = \frac{1}{2} \: ...(2)$

⇒x²-16x-80=0

⇒(x-20)(x+4)=0

Since value of 'y=30' cannot be negativeTherefore, 'x=20' and 'x' Hence, Larger diameter pipe fills in 20hours, and Smaller diameter pipe fills in30 hours.