How many terms of the A.P. 27, 24, 21, … should be taken so that their sum is zero?
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How many terms of the A.P. 27, 24, 21, … should be taken so that their sum is zero?
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The correct option is A
19
Given that AP is 27, 24, 21 …
a = 27 ; d = 24 - 27 = (-3)
Sn=n2(2a+(n−1)d)
Since the sum is 0,
⇒n2(2×27+(n−1)(−3))=0
⇒n(54−3n+3)=0
⇒n(57−3n)=0
⇒n=0 and 57−3n=0
⇒57=3n
∴n=0 and n=19
Since the number of terms cannot be equal to 0, so n = 19
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