Question

$\huge\red{\boxed{\sf QuEStiON}}$

A train travels at a certain average speed of 54km/h and then travels a distance of 63 km at an average speed of 6 km/h more than 1st speed. if it takes 3 hours to complete the total journey ,what is It's first speed?​

Answer 1

Distance =54 km

Let the average speed be x

Distance =63 km

The average speed to cover this distance =x+6

Total time taken =3 hr

t=

S

D

∴

x

54

+

x+6

63

=3

⇒

x(x+6)

54(x+6)+63x

=3

⇒54x+324+63x=3x

2

+18x

⇒3x

2

−99x−324=0

⇒x

2

−33x−108=0

⇒x

2

−36x+3x−108=0

⇒x(x−36)+3(x−36)=0

⇒(x−36)(x+3)=0

Then x=36 and x=−3

x=−3 is not admissible because it is negative

Then x=36

So speed =36 km/hr

hey mate here is the answer

Answer 2

Answer:

here your answer mate...

Step-by-step explanation:

hope it helps you

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