Question

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Derive Coulomb's Law
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Answer 1

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Let’s say that there are two charges q1 and q2. The distance between the charges is ‘r’, and the force of attraction/repulsion between them is ‘F’. Then

F  ∝ q1q2

Or, F  ∝  1/r2

F  = k q1q2/ r2

where k is proportionality constant and equals to 1/4 π ε0. Here, ε0 is the epsilon naught and it signifies permittivity of a vacuum. The value of k comes 9 × 109 Nm2/ C2 when we take the S.I unit of value of ε0 is 8.854 × 10-12 C2 N-1 m-2.

According to this theory, like charges repel each other and unlike charges attract each other. This means charges of same sign will push each other with repulsive forces while charges with opposite signs will pull each other with attractive force.

hope it helps

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Answer 2

Answer:

➜Coulomb’s Law gives an idea about the force between two point charges.

➜By the word point charge, we mean that in physics, the size of linear charged bodies is very small as against the distance between them.

➜If two electrically charged bodies are placed nearby each other there will be an attraction or a repulsion force acting on them depending upon the nature of the charge of the bodies.

➜The formula for the force acting between two electrically charged bodies was first developed by Charles-Augustin de Coulomb and the formula he established for determining the value of force acting to nearby charged objects is known as Coulomb’s law.