Question

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find enthalpy change for combustion of ethanol at 27°C if heat at constant volume is 120(KJ/mol )

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Answer 1

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• Heat of formation of ethanol = 2\times× heat of formation of CO_2CO 2+ 3\times× heat of formation of water - heat of combustion of ethanol

• Heat of formation of ethanol = 2*(-94)+3*(-68.4) -(-327)2∗(−94)+3∗(−68.4)−(−327) = -66.2 kcal−66.2kcal

Answer 2

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☣️.Heat of formation of ethanol = 2\times× heat of formation of CO_2CO 2+ 3\times× heat of formation of water - heat of combustion of ethanol

☣️.Heat of formation of ethanol = 2*(-94)+3*(-68.4) -(-327)2∗(−94)+3∗(−68.4)−(−327) = -66.2 kcal−66.2kcal